Problem
I have spent plenty of time as far as I am newbie in Python. How could I ever decode such a URL:
example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0
to the following in Python 2.7: example.com? title==прaвовая+защита
url=urllib.unquote(url.encode(“utf8”)) returns a very unattractive result.
There is still no solution; any assistance would be greatly appreciated.
Asked by swordholder
Solution #1
The data is UTF-8 encoded bytes escaped with URL quoting, so you want to decode, with urllib.parse.unquote(), which handles decoding from percent-encoded data to UTF-8 bytes and then to text, transparently:
from urllib.parse import unquote
url = unquote(url)
Demo:
>>> from urllib.parse import unquote
>>> url = 'example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0'
>>> unquote(url)
'example.com?title=правовая+защита'
urllib.unquote() is the Python 2 counterpart, however it returns a bytestring, which you’d have to decode manually:
from urllib import unquote
url = unquote(url).decode('utf8')
Answered by Martijn Pieters
Solution #2
You can use urllib.parse if you’re running Python 3.
url = """example.com?title=%D0%BF%D1%80%D0%B0%D0%B2%D0%BE%D0%B2%D0%B0%D1%8F+%D0%B7%D0%B0%D1%89%D0%B8%D1%82%D0%B0"""
import urllib.parse
urllib.parse.unquote(url)
gives:
'example.com?title=правовая+защита'
Answered by pavan
Solution #3
With the requests library, you can also achieve the desired result:
import requests
url = "http://www.mywebsite.org/Data%20Set.zip"
print(f"Before: {url}")
print(f"After: {requests.utils.unquote(url)}")
Output:
$ python3 test_url_unquote.py
Before: http://www.mywebsite.org/Data%20Set.zip
After: http://www.mywebsite.org/Data Set.zip
If you’re currently using requests and don’t want to use another library, this could be useful.
Answered by ivanleoncz
Solution #4
HTML entities can be included in URLs. This also replaces them.
#from urllib import unquote #earlier python version
from urllib.request import unquote
from html import unescape
unescape(unquote('https://v.w.xy/p1/p22?userId=xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx&confirmationToken=7uAf%2fxJoxRTFAZdxslCn2uwVR9vV7cYrlHs%2fl9sU%2frix9f9CnVx8uUT%2bu8y1%2fWCs99INKDnfA2ayhGP1ZD0z%2bodXjK9xL5I4gjKR2xp7p8Sckvb04mddf%2fiG75QYiRevgqdMnvd9N5VZp2ksBc83lDg7%2fgxqIwktteSI9RA3Ux9VIiNxx%2fZLe9dZSHxRq9AA'))
Answered by Roland Puntaier
Post is based on https://stackoverflow.com/questions/16566069/url-decode-utf-8-in-python