In a shell script, how do I pass an argument in Expect through the command line?

Problem

In a shell script, I’m giving an argument to Expect via the command line.

I tried this

#!/usr/bin/expect -f

set arg1 [lindex $argv 0]

spawn lockdis -p
expect "password:" {send "$arg1\r"}
expect "password:" {send "$arg1\r"}
expect "$ "

However, it isn’t working. What can I do about it?

Asked by lk121

Solution #1

If you want to read from arguments, all you have to do is follow the steps below.

set username [lindex $argv 0];
set password [lindex $argv 1];

And print it

send_user "$username $password"

That script is going to print.

$ ./test.exp user1 pass1
user1 pass1

Debug mode is available.

$ ./test.exp -d user1 pass1

Answered by bartimar

Solution #2

This might be a better way to go:

lassign $argv arg1 arg2 arg3

Your method, on the other hand, should work as well. Verify that arg1 has been obtained. Send user “arg1: $arg1n” is an example.

Answered by spbnick

Solution #3

#!/usr/bin/expect
set username [lindex $argv 0]
set password [lindex $argv 1]
log_file -a "/tmp/expect.log"
set timeout 600
spawn /anyscript.sh
expect "username: " { send "$username\r" }
expect "password: " { send "$password\r" }
interact

Answered by user128364

Solution #4

This guide’s response is appealing to me.

It starts the parse argument procedure.

#process to parse command line arguments into OPTS array
proc parseargs {argc argv} {
    global OPTS
    foreach {key val} $argv {
        switch -exact -- $key {
            "-username"   { set OPTS(username)   $val }
            "-password"   { set OPTS(password)   $val }
        }
    }
}
parseargs $argc $argv
#print out parsed username and password arguments
puts -nonewline "username: $OPTS(username) password: $OPTS(password)"

This is just a taste of what’s to come. It’s critical to read the entire handbook and include enough user argument checks.

Answered by Duffmannen

Solution #5

It’s worth noting that argv 0 can also be the name of the script you’re calling. As a result, argv 0 will not work if you run it that way.

I’m a runner.

expect script.exp  password

As a result, argv 1 equals password and argv 0 equals script.exp.

Answered by Sid Dakota

Post is based on https://stackoverflow.com/questions/17059682/how-to-pass-argument-in-expect-through-the-command-line-in-a-shell-script