# How can you find out how wide and tall a multi-dimensional array is?

## Problem

I’ve set up an array:

``````int [,] ary;
// ...
int nArea = ary.Length; // x*y or total area
``````

This is all well and good, but I need to know how wide this array is in the x and y dimensions individually. Namely, ary.Length might return 12 – but does that mean the array is 4 high and 3 wide, or 6 high and 2 wide?

What is the best way for me to get this information?

## Solution #1

You make use of Array. With the index of the dimension you want to retrieve, use GetLength.

## Solution #2

Use GetLength(), rather than Length.

``````int rowsOrHeight = ary.GetLength(0);
int colsOrWidth = ary.GetLength(1);
``````

## Solution #3

``````// Two-dimensional GetLength example.
int[,] two = new int[5, 10];
Console.WriteLine(two.GetLength(0)); // Writes 5
Console.WriteLine(two.GetLength(1)); // Writes 10
``````

## Solution #4

Some of the other posts are confused about which dimension is which. Here’s an NUNIT test that shows how 2D arrays work in C#

``````[Test]
public void ArraysAreRowMajor()
{
var myArray = new int[2,3]
{
{1, 2, 3},
{4, 5, 6}
};

int rows = myArray.GetLength(0);
int columns = myArray.GetLength(1);
Assert.AreEqual(2,rows);
Assert.AreEqual(3,columns);
Assert.AreEqual(1,myArray[0,0]);
Assert.AreEqual(2,myArray[0,1]);
Assert.AreEqual(3,myArray[0,2]);
Assert.AreEqual(4,myArray[1,0]);
Assert.AreEqual(5,myArray[1,1]);
Assert.AreEqual(6,myArray[1,2]);
}
``````

``````ary.GetLength(0)