How can you find out how wide and tall a multi-dimensional array is?

Problem

I’ve set up an array:

int [,] ary;
// ...
int nArea = ary.Length; // x*y or total area

This is all well and good, but I need to know how wide this array is in the x and y dimensions individually. Namely, ary.Length might return 12 – but does that mean the array is 4 high and 3 wide, or 6 high and 2 wide?

What is the best way for me to get this information?

Asked by Giffyguy

Solution #1

You make use of Array. With the index of the dimension you want to retrieve, use GetLength.

Answered by Reed Copsey

Solution #2

Use GetLength(), rather than Length.

int rowsOrHeight = ary.GetLength(0);
int colsOrWidth = ary.GetLength(1);

Answered by David Yaw

Solution #3

// Two-dimensional GetLength example.
int[,] two = new int[5, 10];
Console.WriteLine(two.GetLength(0)); // Writes 5
Console.WriteLine(two.GetLength(1)); // Writes 10

Answered by Satish Wadkar

Solution #4

Some of the other posts are confused about which dimension is which. Here’s an NUNIT test that shows how 2D arrays work in C#

[Test]
public void ArraysAreRowMajor()
{
    var myArray = new int[2,3]
        {
            {1, 2, 3},
            {4, 5, 6}
        };

    int rows = myArray.GetLength(0);
    int columns = myArray.GetLength(1);
    Assert.AreEqual(2,rows);
    Assert.AreEqual(3,columns);
    Assert.AreEqual(1,myArray[0,0]);
    Assert.AreEqual(2,myArray[0,1]);
    Assert.AreEqual(3,myArray[0,2]);
    Assert.AreEqual(4,myArray[1,0]);
    Assert.AreEqual(5,myArray[1,1]);
    Assert.AreEqual(6,myArray[1,2]);
}

Answered by Peter Neorr

Solution #5

ary.GetLength(0) 
ary.GetLength(1)

for 2 dimensional array

Answered by Ali Tarhini

Post is based on https://stackoverflow.com/questions/4260207/how-do-you-get-the-width-and-height-of-a-multi-dimensional-array