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Get the name of the type without the complete namespace


The following is the code I have:

return "[Inserted new " + typeof(T).ToString() + "]";



The whole name, including the namespace, is returned.

Is it possible to get the class name alone (without any namespace qualifiers)?

Asked by leora

Solution #1

typeof(T).Name // class name, no namespace
typeof(T).FullName // namespace and class name
typeof(T).Namespace // namespace, no class name

Answered by Tim Robinson

Solution #2

To acquire type parameters for generic types, do this:

public static string CSharpName(this Type type)
    var sb = new StringBuilder();
    var name = type.Name;
    if (!type.IsGenericType) return name;
    sb.Append(name.Substring(0, name.IndexOf('`')));
    sb.Append(string.Join(", ", type.GetGenericArguments()
                                    .Select(t => t.CSharpName())));
    return sb.ToString();

It’s not the most elegant solution (due to the recursion), but it gets the job done. The following are examples of outputs:

Dictionary<String, Object>

Answered by gregsdennis

Solution #3

take advantage of (Type Properties)

 Name   Gets the name of the current member. (Inherited from MemberInfo.)
 Example : typeof(T).Name;

Answered by Pranay Rana

Solution #4

You can use nameof expression: after C# 6.0 (included).

using Stuff = Some.Cool.Functionality  
class C {  
    static int Method1 (string x, int y) {}  
    static int Method1 (string x, string y) {}  
    int Method2 (int z) {}  
    string f<T>() => nameof(T);  

var c = new C()  

nameof(C) -> "C"  
nameof(C.Method1) -> "Method1"   
nameof(C.Method2) -> "Method2"  
nameof(c.Method1) -> "Method1"   
nameof(c.Method2) -> "Method2"  
nameof(z) -> "z" // inside of Method2 ok, inside Method1 is a compiler error  
nameof(Stuff) = "Stuff"  
nameof(T) -> "T" // works inside of method but not in attributes on the method  
nameof(f) -> “f”  
nameof(f<T>) -> syntax error  
nameof(f<>) -> syntax error  
nameof(Method2()) -> error “This expression does not have a name”  

Note that nameof does not return the runtime Type of the underlying object; it is only a compile-time input. If a method accepts an IEnumerable, nameof returns “IEnumerable,” even if the real object is “List.”

Answered by Stas Boyarincev

Solution #5


Answered by Datoon

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