Django: Show the Value of a Choice

Problem

models.py:

class Person(models.Model):
    name = models.CharField(max_length=200)
    CATEGORY_CHOICES = (
        ('M', 'Male'),
        ('F', 'Female'),
    )
    gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
    to_be_listed = models.BooleanField(default=True)
    description = models.CharField(max_length=20000, blank=True)

views.py:

def index(request):
    latest_person_list2 = Person.objects.filter(to_be_listed=True)
    return object_list(request, template_name='polls/schol.html',
                       queryset=latest_person_list, paginate_by=5)

When I call person.gender on the template, I receive ‘M’ or ‘F’ instead of ‘Male’ or ‘Female.’

How do I display the value (‘Male’ or ‘Female’) rather than the code (‘M’/’F’) instead of the code (‘M’/’F’)?

Asked by Shankze

Solution #1

It appears like you were on the right track – get FOO display() is exactly what you’re looking for:

You don’t use () in the name of a method in templates. Perform the following actions:

{{ person.get_gender_display }}

Answered by jMyles

Solution #2

In Views

person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()

In Template

{{ person.get_gender_display }}

Documentation of get_FOO_display()

Answered by Muhammad Faizan Fareed

Solution #3

Others have suggested that you use the get FOO display method. This is what I’m using:

def get_type(self):
    return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]

It iterates through all of the options available for a given item until it finds one that matches the item’s type.

Answered by Daniel O’Brien

Post is based on https://stackoverflow.com/questions/4320679/django-display-choice-value